2x^4-x^2+2=0

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Solution for 2x^4-x^2+2=0 equation:


Simplifying
2x4 + -1x2 + 2 = 0

Reorder the terms:
2 + -1x2 + 2x4 = 0

Solving
2 + -1x2 + 2x4 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
1 + -0.5x2 + x4 = 0

Move the constant term to the right:

Add '-1' to each side of the equation.
1 + -0.5x2 + -1 + x4 = 0 + -1

Reorder the terms:
1 + -1 + -0.5x2 + x4 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -0.5x2 + x4 = 0 + -1
-0.5x2 + x4 = 0 + -1

Combine like terms: 0 + -1 = -1
-0.5x2 + x4 = -1

The x term is -0.5x2.  Take half its coefficient (-0.25).
Square it (0.0625) and add it to both sides.

Add '0.0625' to each side of the equation.
-0.5x2 + 0.0625 + x4 = -1 + 0.0625

Reorder the terms:
0.0625 + -0.5x2 + x4 = -1 + 0.0625

Combine like terms: -1 + 0.0625 = -0.9375
0.0625 + -0.5x2 + x4 = -0.9375

Factor a perfect square on the left side:
(x2 + -0.25)(x2 + -0.25) = -0.9375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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